to check number is armstrong or not

#include<stdio.h>
#include<conio.h>
void main()
{
   int num,x,digit,sumqube=0;
   clrscr();
   printf("\n enter the number:\n");
   scanf("%d",&num);
   x=num;
   while(x>0)
   {
   digit=x%10;
   sumqube=sumqube+(digit*digit*digit);
   x=x/10;
   }
   if(sumqube==num)
   printf("number is armstrong\n");
   else
   printf("\n number is not armstrong");
   getch();
   }